BIOL 1009, Quiz 2 Study Guide
Last updated 10/23/1999.
SOME GENETICS HOMEWORK PROBLEMS - KEY (1-6)

1.    a) The F1 are all Bb.        b) Bb x Bb  - 1 BB: 2 Bb: 1 bb, 3 black : 1 yellow

2.    a) black fur (BB or Bb)  x  yellow fur (bb)
       b) BB x bb -  all Bb, all black  or Bb x bb -  1 Bb:1bb, 1 black: 1 yellow
       c) black fur - Bb, yellow fur - bb, offspring - bb

3.    a) BB or Bb x BB or Bb
       b) BB x BB - all BB, all black  or
           BB x Bb (or Bb x BB) - 1 BB: 1 Bb, all black or
           Bb x Bb  - 1 BB: 2 Bb: 1 bb, 3 black : 1 yellow
       c) both parents - Bb, offspring bb

4.                P1 = BBTT x bbtt                F1 = 4 BbTt : 0, all black with long tails
    a) BbTt and BbTt
    b) BbTt x BbTt
          genotype ratio:
            F2 = 1 BBTT : 2 BBTt : 2 BbTT : 4 BbTt : 1 BBtt : 2 Bbtt : 1 bbTT : 2 bbTt : 1 bbtt
          phenotype ratio = 9/16 black with long tails (B_T_)
                                     3/16 black with short tails (B_tt )
                                     3/16 yellow with long tails (bbT_ )
                                     1/16 yellow with short tails (1 bbtt)

5.    a)  black, short-tailed  rugrat: BBtt or Bbtt                         yellow, short-tailed rugrat: bbtt
       b)              BBtt x bbtt:                                                Bbtt x bbtt:
                        4 Bbtt : 0                                                1 Bbtt : 1 bbtt
                all black with short tails                1/2 black, short tail; 1/2 yellow, short tail
       c) bbtt
       d)  black, short-tailed  rugrat: Bbtt                                      yellow, short-tailed rugrat: bbtt

6.    a) black, short-tailed rugrat:  BBtt or Bbtt         yellow, long-tailed rugrat: bbTT or bbTt
       b)        BBtt x bbTT:                                                BBtt x bbTt:
                    4 BbTt : 0                                        1 BbTt : 1 Bbtt, all black
            all black with long tails                1/2 with long tails: 1/2 with short tails

                   Bbtt x bbTT:                                                    Bbtt x bbTt:
            1 BbTt : 1 bbTt, all with long tails                1 BbTt : 1 bbTt : 1 Bbtt : 1 bbtt
         1/2 black : 1/2 yellow                                1/4 black, long tail; 1/4 yellow, long tail
                                                                        1/4 black, short tail; 1/4 yellow, short tail
       c) BbTt



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